Question

When ${}_{15}{P}^{30}$ decays to become ${}_{14}S{i}^{30}$ which particle is released ?

• A. neutron
• B. electron
• C. meson
• D. positron

Answer 1

Answer: (D)

The nuclear reaction : ${}_{15}{P}^{30}\to 14S{i}^{30}+{}_{+1}{e}^0$
Thus a positron is emitted during the decay of ${}_{15}{P}^{30}\text{ into }{}_{14}S{i}^{30}$.