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Q. When $_{15} P ^{30}$ decays to become $_{14} Si ^{30}$ which particle is released ?

KCETKCET 1997Atoms

Solution:

The nuclear reaction : ${ }_{15} P ^{30} \rightarrow 14 Si ^{30}+{ }_{+1} e ^{0}$
Thus a positron is emitted during the decay of ${ }_{15} P ^{30} \text { into }{ }_{14} Si ^{30} $.