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Question
Physics
In the nuclear decay given below AZ X arrow A Z+1 Y arrow A-AZ-1B * arrow A-AZ-1B, the particles emitted in the sequence are
Q. In the nuclear decay given below
Z
A
​
X
→
Z
+
1
A
​
Y
→
Z
−
1
A
−
A
​
B
∗
→
Z
−
1
A
−
A
​
B
,
the particles emitted in the sequence are
3645
246
AIPMT
AIPMT 2009
Atoms
Report Error
A
γ
,
β
,
α
13%
B
β
,
γ
,
α
17%
C
α
,
β
,
γ
30%
D
β
,
α
,
γ
39%
Solution:
Z
A
​
X
β
−
​
Z
+
1
A
​
Y
α
​
Z
−
1
A
−
4
​
B
∗
γ
​
Z
−
1
A
−
4
​
B
First X decays by
β
emission emitting
v
, antineutrino simultaneously.
Y
emits
α
resulting in the excited level of
B
which in tum emits a
γ
ray.
∴
β
,
α
,
γ
is the answer.