Question

In the molecular orbital diagram for the molecular ion, $N_2{}^{+}$, the number of electrons in the ${\sigma }_{2p}$ molecular orbital is :

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (B)

The arrangement of electrons in molecular orbitals is as follows:

$\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\pi 2p_y^2=\pi 2p_z^2,\sigma 2p_x^1$