In the method using the transformers, assume that the ratio of - the number of turns in the primary to that in the secondary in the step-up transformer is 1:10.1 f the power to the consumers has to be supplied at 200V, the ratio of the number of turns in the primary to that in the secondary in the step-down transformer is

Question

In the method using the transformers, assume that the ratio of - the number of turns in the primary to that in the secondary in the step-up transformer is 1:10.1 f the power to the consumers has to be supplied at 200V, the ratio of the number of turns in the primary to that in the secondary in the step-down transformer is (A) 200: 1 (B) 150: 1 (C) 100: 1 (D) 50: 1

Tardigrade Admin · Accepted Answer

During step-up, (Np/Ns) = (Vp/Vs) or (1/10) = (4000/Vs) or Vs = 40000 V In step down transformer, (Np/Ns) = (Vp/Vs) = (40000/200) = (200/1)

200 : 1

150 : 1

100 : 1

50 : 1

During step-up,
$\frac{N _{p}}{N _{s}} = \frac{V _{p}}{V s} or \frac{1}{10} = \frac{4000}{V _{s}}$
or $V_{s} = 40000 V$
In step down transformer,
$\frac{N _{p}}{N _{s}} = \frac{V _{p}}{V s} = \frac{40000}{200} = \frac{200}{1}$

200 : 1

150 : 1

100 : 1

50 : 1

During step-up, Ns​Np​​=VsVp​​or101​=Vs​4000​ or Vs​=40000V In step down transformer, Ns​Np​​=VsVp​​=20040000​=1200​

During step-up,
$\frac{N _{p}}{N _{s}} = \frac{V _{p}}{V s} or \frac{1}{10} = \frac{4000}{V _{s}}$
or $V_{s} = 40000 V$
In step down transformer,
$\frac{N _{p}}{N _{s}} = \frac{V _{p}}{V s} = \frac{40000}{200} = \frac{200}{1}$