In the lead-acid battery during charging, the cathode reaction is

Question

In the lead-acid battery during charging, the cathode reaction is (A) formation of PbO2  (B) formation of PbSO4  (C) reduction of Pb2+ to Pb  (D) decomposition of Pb at the anode

Tardigrade Admin · Accepted Answer

The cell reactions during charging of lead storage battery are
At anode

P b S O_{4} (s) + 2 e^{-} \to P b (s) + S O_{4}^{2 -} (a q)

At cathode

P b S O_{4} (s) + 2 H_{2} O \to P b O_{2} (s) + S O_{4}^{2 -} (a q) - 4 H^{+} + 2 e^{-}

Thus, at cathode, formation of

P b O_{2}

takes place.

Q. In the lead-acid battery during charging, the cathode reaction is

formation of $P b O_{2}$

formation of $P b S O_{4}$

reduction of $P b^{2 +}$ to $P b$

decomposition of $P b$ at the anode

The cell reactions during charging of lead storage battery are
At anode $P b S O_{4} (s) + 2 e^{-} \to P b (s) + S O_{4}^{2 -} (a q)$
At cathode
$P b S O_{4} (s) + 2 H_{2} O \to P b O_{2} (s) + S O_{4}^{2 -} (a q) - 4 H^{+} + 2 e^{-}$
Thus, at cathode, formation of $P b O_{2}$ takes place.

Q. In the lead-acid battery during charging, the cathode reaction is

formation of PbO2​

formation of PbSO4​

reduction of Pb2+ to Pb

decomposition of Pb at the anode

The cell reactions during charging of lead storage battery are At anode PbSO4​(s)+2e−→Pb(s)+SO42−​(aq) At cathode PbSO4​(s)+2H2​O→PbO2​(s)+SO42−​(aq)−4H++2e− Thus, at cathode, formation of PbO2​ takes place.

formation of $P b O_{2}$

formation of $P b S O_{4}$

reduction of $P b^{2 +}$ to $P b$

decomposition of $P b$ at the anode

The cell reactions during charging of lead storage battery are
At anode $P b S O_{4} (s) + 2 e^{-} \to P b (s) + S O_{4}^{2 -} (a q)$
At cathode
$P b S O_{4} (s) + 2 H_{2} O \to P b O_{2} (s) + S O_{4}^{2 -} (a q) - 4 H^{+} + 2 e^{-}$
Thus, at cathode, formation of $P b O_{2}$ takes place.