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Tardigrade
Question
Mathematics
In the interval (0, (π/2)) area lying between the curves y = tan x, y = cot x and x-axis is
Q. In the interval
(
0
,
2
π
)
area lying between the curves
y
=
t
an
x
,
y
=
co
t
x
and
x
-axis is
2006
198
Application of Integrals
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A
3
log
2
sq. units
B
2
log
2
sq. units
C
log
2
sq. units
D
2
1
log
2
sq. units
Solution:
We have,
y
=
t
an
x
…
(
i
)
and
y
=
co
t
x
…
(
ii
)
t
an
x
and
co
t
x
intersect at
π
/4
Required area = area of shaded region
=
0
∫
π
/4
t
an
x
d
x
+
π
/4
∫
π
/2
co
t
x
d
x
=
[
−
l
o
g
cos
x
]
0
π
/4
+
[
l
o
g
s
in
x
]
π
/4
π
/2
=
−
l
o
g
2
1
−
l
o
g
2
1
=
2
l
o
g
2
=
l
o
g
2
sq. units