In the indicator diagram, net amount of work done will be

Question

In the indicator diagram, net amount of work done will be (A) positive (B) zero (C) infinity (D) negative

Tardigrade Admin · Accepted Answer

Figure shows that loop 1 is anti-clockwise, therefore W1 is negative, loop 2 is clockwise, therefore W2 is positive. Also, loop 2 is bigger. W2>W1 Hence, net work done W=-W1+W2=W2-W1=(+) ve

Q. In the indicator diagram, net amount of work done will be

positive

zero

infinity

negative

Figure shows that loop 1 is anti-clockwise, therefore $W_{1}$ is negative, loop 2 is clockwise, therefore $W_{2}$ is positive. Also, loop 2 is bigger.
$W_{2} > W_{1}$
Hence, net work done $W = - W_{1} + W_{2} = W_{2} - W_{1} = (+)$ ve

Q. In the indicator diagram, net amount of work done will be

positive

zero

infinity

negative

Figure shows that loop 1 is anti-clockwise, therefore W1​ is negative, loop 2 is clockwise, therefore W2​ is positive. Also, loop 2 is bigger. W2​>W1​ Hence, net work done W=−W1​+W2​=W2​−W1​=(+) ve

Figure shows that loop 1 is anti-clockwise, therefore $W_{1}$ is negative, loop 2 is clockwise, therefore $W_{2}$ is positive. Also, loop 2 is bigger.
$W_{2} > W_{1}$
Hence, net work done $W = - W_{1} + W_{2} = W_{2} - W_{1} = (+)$ ve