Question

In the given network, if potential difference between $p$ and $q$ is $2V$ and $C_2=3C_1$, then find the potential difference (in volt) between $a$ and $b$.

Answer 1

Answer: 30

$Q_{pq}=2C_2=6C_1=Q_{bp}$
$\therefore V_{bp}=\frac{6C_1}{C_1}=6V$
$\therefore V_{bq}=6+2=8V$
Total charge flown through
$ab=C_2{V}_{bq}+C_1{V}_{bp}$
$=3C_1\times 8+C_1\times 6=30C_1$
$\therefore V_{ab}=\frac{Q_{\text{total }}}{C_{ab}}=\frac{30C_1}{C_1}$
$=30V$