In the given LCR AC circuit, the effective current (in ampere) flowing through the circuit is.

Question

In the given LCR AC circuit, the effective current (in ampere) flowing through the circuit is. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-r7vw58uvzie32yzo.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

R=50Ω XL=ω L=50Ω XL=(1/ω C)=100Ω ⇒ Z=√R2 + (XL - XC)2 Z=50√2 Ω Irms=(Vrms/Z)=(200 / √2/50 √2)=2A

Q. In the given $L CR$ $A C$ circuit, the effective current (in ampere) flowing through the circuit is.

$R = 50Ω$
$X_{L} = ω L = 50Ω$
$X_{L} = \frac{1}{ω C} = 100Ω$
$\Rightarrow Z = R^{2} + (X_{L} - X_{C})^{2}$
$Z = 502 Ω$
$I_{r m s} = \frac{V _{r m s}}{Z} = \frac{200/ 2}{50 2} = 2 A$

Q. In the given LCR AC circuit, the effective current (in ampere) flowing through the circuit is.

R=50Ω XL​=ωL=50Ω XL​=ωC1​=100Ω ⇒Z=R2+(XL​−XC​)2​ Z=502​Ω Irms​=ZVrms​​=502​200/2​​=2A

Q. In the given $L CR$ $A C$ circuit, the effective current (in ampere) flowing through the circuit is.

$R = 50Ω$
$X_{L} = ω L = 50Ω$
$X_{L} = \frac{1}{ω C} = 100Ω$
$\Rightarrow Z = R^{2} + (X_{L} - X_{C})^{2}$
$Z = 502 Ω$
$I_{r m s} = \frac{V _{r m s}}{Z} = \frac{200/ 2}{50 2} = 2 A$