Question

In the given figure the steady state current in the circuit is

• A. Zero
• B. 0.6 A
• C. 0.9 A
• D. 1.5 A

Answer 1

Answer: (D)

In the steady state there is no current in the capacitor branch.
In the given circuit the resistors of $2\Omega$ and $3\Omega$ are connected in parallel hence, equivalent resistance is
$\frac{1}{R}=\frac{1}{2}+\frac{1}{3}=\frac{5}{6}$
$\therefore R^{\prime }=\frac{6}{5}\Omega$
Also in steady state, the circuit is shown as. Resistors of $\frac{6}{5}\Omega$ and $2.8\Omega$ are connected in series
Hence, $R^{\prime \prime }=\frac{6}{5}\Omega +2.8\Omega$
$=1.2\Omega +2.8\Omega$
$=4.0\Omega$
From Ohms law, Current $i=\frac{V}{R}=\frac{6}{4.0}=1.5A$