In the given figure, the block of mass m is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point ' B ' is :

Question

In the given figure, the block of mass m is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point ' B ' is : (A) (1/2) mg y 02 (B) (1/2) mgy 2 (C) m g( y - y 0) (D) m g y0

Tardigrade Admin · Accepted Answer

Work done by gravity = K B - K A mgy 0= K B -0 K B = mgy 0

Q. In the given figure, the block of mass $m$ is dropped from the point $^{'} A^{'}$ . The expression for kinetic energy of block when it reaches point ' $B$ ' is :

$\frac{1}{2} m g y_{0}^{2}$

$\frac{1}{2} m g y^{2}$

$m g (y - y_{0})$

$m g y_{0}$

Work done by gravity $= K_{B} - K_{A}$
$m g y_{0} = K_{B} - 0$
$K_{B} = m g y_{0}$

Q. In the given figure, the block of mass m is dropped from the point ′A′. The expression for kinetic energy of block when it reaches point ' B ' is :

21​mgy02​

21​mgy2

mg(y−y0​)

mgy0​