In the given figure, the axial magnetic field at a point P, at a distance r from the centre O of a solenoid is (Consider m as the magnitude of the magnetic moment of the solenoid).

Question

In the given figure, the axial magnetic field at a point P, at a distance r from the centre O of a solenoid is (Consider m as the magnitude of the magnetic moment of the solenoid). (A) B=(2 μ0/3 π) (2 m/r3) (B) B=(4/3) (μ0/π) (2 m/r3) (C) B=(μ0/4 π) (2 m/r3) (D) B=(μ0/2 π) (2 m/r3)

Tardigrade Admin · Accepted Answer

Magnitude of the magnetic moment of the solenoid is, m=n(2 l) I(π a2) Thus, B=(μ0/4 π) ⋅ (2 M/r3)

Q. In the given figure, the axial magnetic field at a point $P$ , at a distance $r$ from the centre $O$ of a solenoid is (Consider $m$ as the magnitude of the magnetic moment of the solenoid).

$B = \frac{2 μ _{0}}{3 π} \frac{2 m}{r ^{3}}$

$B = \frac{4}{3} \frac{μ _{0}}{π} \frac{2 m}{r ^{3}}$

$B = \frac{μ _{0}}{4 π} \frac{2 m}{r ^{3}}$

$B = \frac{μ _{0}}{2 π} \frac{2 m}{r ^{3}}$

Magnitude of the magnetic moment of the solenoid is,
$m = n (2 l) I (π a^{2})$
Thus, $B = \frac{μ _{0}}{4 π} \cdot \frac{2 M}{r ^{3}}$

Q. In the given figure, the axial magnetic field at a point P, at a distance r from the centre O of a solenoid is (Consider m as the magnitude of the magnetic moment of the solenoid).

B=3π2μ0​​r32m​

B=34​πμ0​​r32m​

B=4πμ0​​r32m​

B=2πμ0​​r32m​