Question

In the given figure of circuit, the voltmeter reads $50V$. Determine the value of capacitance $C$ ?

• A. $2\mu F$
• B. $2.5\mu F$
• C. $3\mu F$
• D. $5\mu F$

Answer 1

Answer: (B)

$X_L=X_C$
$\Rightarrow 2\pi fL=\frac{1}{2\pi fC}$
$\Rightarrow C=\frac{1}{4{\pi }^2{f}^{2}L}$
$=\frac{1}{4\times 10\times 10^6\times 10\times 10^{-3}}$
$=2.5\mu F$