These are numeric entry type questions. In the given figure, a quadrilateral ABCD is inscribed in a circle and BD is a diagonal passing through the centre of the circle ' O '. Then, angle BOC + angle AOD =

Question

These are numeric entry type questions. In the given figure, a quadrilateral ABCD is inscribed in a circle and BD is a diagonal passing through the centre of the circle ' O '. Then, angle BOC + angle AOD = (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/a22aff42d471746795c7d36028165bcd-.png" /> ∴ angle BOC + angle AOD =2 angle BDC +2 angle ABD = 80°+60°=140°

Q. These are numeric entry type questions.
In the given figure, a quadrilateral $A BC D$ is inscribed in a circle and $B D$ is a diagonal passing through the centre of the circle ' $O$ '. Then, $∠ BOC + ∠ A O D =$ ____

$∴ ∠ BOC + ∠ A O D = 2∠ B D C + 2∠ A B D =$
$8 0^{\circ} + 6 0^{\circ} = 14 0^{\circ}$

Q. These are numeric entry type questions. In the given figure, a quadrilateral ABCD is inscribed in a circle and BD is a diagonal passing through the centre of the circle ' O '. Then, ∠BOC+∠AOD=____

∴∠BOC+∠AOD=2∠BDC+2∠ABD= 80∘+60∘=140∘

Q. These are numeric entry type questions.
In the given figure, a quadrilateral $A BC D$ is inscribed in a circle and $B D$ is a diagonal passing through the centre of the circle ' $O$ '. Then, $∠ BOC + ∠ A O D =$ ____

$∴ ∠ BOC + ∠ A O D = 2∠ B D C + 2∠ A B D =$
$8 0^{\circ} + 6 0^{\circ} = 14 0^{\circ}$