In the given diagram S1 and S2 are identical springs. The frequency of oscillation of the mass m is f. If one of the springs is removed, then frequency will be

Question

In the given diagram S1 and S2 are identical springs. The frequency of oscillation of the mass m is f. If one of the springs is removed, then frequency will be <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/9a9fc787cd00b092ec768d0496028de5-.png" /> (A) f (B) 2 f (C) √2 f (D) (f/√2)

Tardigrade Admin · Accepted Answer

Effective spring constant, k=2 k Frequency of oscillation, f=(1/2 π) √(2 k/m) When one spring is removed, then spring factor =k New frequency of oscillation will be constant f' =(1/2 π) √(k/m) =(f/√2)

Q. In the given diagram $S_{1}$ and $S_{2}$ are identical springs. The frequency of oscillation of the mass $m$ is $f$ . If one of the springs is removed, then frequency will be

$f$

$2 f$

$2 f$

$\frac{f}{2}$

Effective spring constant, $k = 2 k$
Frequency of oscillation, $f = \frac{1}{2 π} \frac{2 k}{m}$
When one spring is removed, then spring factor $= k$
New frequency of oscillation will be constant
$f^{'} = \frac{1}{2 π} \frac{k}{m}$
$= \frac{f}{2}$

Q. In the given diagram S1​ and S2​ are identical springs. The frequency of oscillation of the mass m is f. If one of the springs is removed, then frequency will be

f

2f

2​f

2​f​

Effective spring constant, k=2k Frequency of oscillation, f=2π1​m2k​​ When one spring is removed, then spring factor =k New frequency of oscillation will be constant f′=2π1​mk​​ =2​f​

Q. In the given diagram $S_{1}$ and $S_{2}$ are identical springs. The frequency of oscillation of the mass $m$ is $f$ . If one of the springs is removed, then frequency will be

$f$

$2 f$

$2 f$

$\frac{f}{2}$

Effective spring constant, $k = 2 k$
Frequency of oscillation, $f = \frac{1}{2 π} \frac{2 k}{m}$
When one spring is removed, then spring factor $= k$
New frequency of oscillation will be constant
$f^{'} = \frac{1}{2 π} \frac{k}{m}$
$= \frac{f}{2}$