Question

In the given circuit, what will be the equivalent resistance between the points $A$ and $B$ ?

• A. $10/3\Omega$
• B. $20/3\Omega$
• C. $10/5\Omega$
• D. $5\Omega$

Answer 1

Answer: (A)

$\because \frac{2}{3}=\frac{4}{6}$
$\therefore$ Given, circuit is a balanced Wheatstone's Bridge.
So, $10\Omega$ resistance will be ineffective.
Equivalent resistance of upper arms
$R_1=2+3=5\Omega$
$\therefore$ Equivalent resistance of lower arms
$R_2=4+6=10\Omega$
$R_{AB}=\frac{R_1{R}_2}{R_1+R_2}$
$=\frac{5\times 10}{5+10}$
$=\frac{50}{10}=\frac{10}{3}\Omega$