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Tardigrade
Question
Physics
In the given circuit the potential at point B is zero, the potential at points A and D will be
Q. In the given circuit the potential at point
B
is zero, the potential at points
A
and
D
will be
3512
176
Current Electricity
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A
V
A
=
4
V
;
V
D
=
9
V
29%
B
V
A
=
3
V
;
V
D
=
4
V
22%
C
V
A
=
9
V
;
V
D
=
3
V
17%
D
V
A
=
4
V
;
V
D
=
3
V
33%
Solution:
V
A
−
V
B
=
2
×
2
=
4
V
∴
V
A
−
0
=
4
V
⇒
V
A
=
4
V
According to question
V
B
=
0
Point
D
is connected to positive terminal of battery of emf
3
V
.