Question

In the given circuit the current through the zener diode is :-

• A. 10 mA
• B. 6.67 mA
• C. 5 mA
• D. 3.33 mA

Answer 1

Answer: (D)

$I_L=\frac{V_z}{R_L}=\frac{10}{1500}A$
$I=\frac{V-V_z}{R}=\frac{15-10}{500}=\frac{5}{100}A$
$I_Z=I-I_L=\frac{5}{100}-\frac{10}{1500}$
$=3.33mA$