Thank you for reporting, we will resolve it shortly
Q.
In the given circuit the current through the zener diode is :-
Solution:
$I _{ L }=\frac{ V _{ z }}{ R _{ L }}=\frac{10}{1500} A$
$I =\frac{ V - V _{ z }}{ R }=\frac{15-10}{500}=\frac{5}{100} A$
$I _{ Z }= I - I _{ L }=\frac{5}{100}-\frac{10}{1500}$
$=3.33 \,mA$