In the given circuit assuming point A to be at zero potential, use Kirchhoff s rules to determine the potential at point B.

Question

In the given circuit assuming point A to be at zero potential, use Kirchhoff s rules to determine the potential at point B. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/4f00620f43eebe861906977fef2bd127-.png" /> (A) 2V (B) 6V (C) 10V (D) 0V

Tardigrade Admin · Accepted Answer

According to Kirchhoff's first rule, current in arm

D C = 3 - 1 = 2 A

Pot. diff. across

2Ω = 2 \times 2 = 4 V

As point

A

is at zero potential, so potential of point

C

is

V_{c} = 2 V

Now,

V_{D} - V_{C} = 4

or

V_{D} - 2 = 4

or

V_{D} = 6 V

Here,

V_{D} - V_{B} = 4

or

V_{B} = V_{D} - 4 = 6 - 4 = 2 V

Q. In the given circuit assuming point A to be at zero potential, use Kirchhoff s rules to determine the potential at point B.

$2 V$

$6 V$

$10 V$

$0 V$

Q. In the given circuit assuming point A to be at zero potential, use Kirchhoff s rules to determine the potential at point B.

2V

6V

10V

0V

According to Kirchhoff's first rule, current in arm DC=3−1=2A Pot. diff. across 2Ω=2×2=4V As point A is at zero potential, so potential of point C is Vc​=2V Now, VD​−VC​=4 or VD​−2=4 or VD​=6V Here, VD​−VB​=4 or VB​=VD​−4=6−4=2V

$2 V$

$6 V$

$10 V$

$0 V$