In the given circuit, a charge of + 80 μ C is given to upper plate of a 4 μ F capacitor. At steady state the charge on the upper plate of the 3 μ F capacitor is

Question

In the given circuit, a charge of + 80 μ C is given to upper plate of a 4 μ F capacitor. At steady state the charge on the upper plate of the 3 μ F capacitor is (A) 60 μ C  (B) 48 μ C  (C) 80 μ C  (D) 0 μ C

Tardigrade Admin · Accepted Answer

The net charge on upper plates both capacitor (2 μ F and 3 μ F ) will be +80 μ C, so charge on upper plate of 3 μ C capacitor will be q=((3/3+2))(80 μ C ) q=(3/5) × 80=48 μ C

Q. In the given circuit, a charge of $+ 80 μ C$ is given to upper plate of a $4 μ F$ capacitor. At steady state the charge on the upper plate of the $3 μ F$ capacitor is

$60 μ C$

$48 μ C$

$80 μ C$

$0 μ C$

The net charge on upper plates both capacitor $(2 μ F$ and $3 μ F$ ) will be $+ 80 μ C$ , so charge on upper plate of $3 μ C$ capacitor will be
$q = (\frac{3}{3 + 2}) (80 μ C)$
$q = \frac{3}{5} \times 80 = 48 μ C$

Q. In the given circuit, a charge of +80μC is given to upper plate of a 4μF capacitor. At steady state the charge on the upper plate of the 3μF capacitor is

60μC

48μC

80μC

0μC