In the given Cannizzaro reaction, the slowest step is: 2C6H5CHO oversetOH- arrow C6H5CH2OH+C6H5COO-

Question

In the given Cannizzaro reaction, the slowest step is: 2C6H5CHO oversetOH- arrow C6H5CH2OH+C6H5COO- (A) The attack by OH- on the carbonyl group. (B) The transfer of the hydride to the carbonyl group. (C) The exchange of protons can be slow steps. (D) All the above.

Tardigrade Admin · Accepted Answer

The transfer of the hydride to the carbonyl group.

Q. In the given Cannizzaro reaction, the slowest step is:
$2 C_{6} H_{5} C H O \to O H^{-} C_{6} H_{5} C H_{2} O H + C_{6} H_{5} CO O^{-}$

The attack by $O H^{-}$ on the carbonyl group.

The transfer of the hydride to the carbonyl group.

The exchange of protons can be slow steps.

All the above.

The transfer of the hydride to the carbonyl group.

Q. In the given Cannizzaro reaction, the slowest step is: 2C6​H5​CHO→OH−C6​H5​CH2​OH+C6​H5​COO−

The attack by OH− on the carbonyl group.

The transfer of the hydride to the carbonyl group.

The exchange of protons can be slow steps.

All the above.

The transfer of the hydride to the carbonyl group.

Q. In the given Cannizzaro reaction, the slowest step is:
$2 C_{6} H_{5} C H O \to O H^{-} C_{6} H_{5} C H_{2} O H + C_{6} H_{5} CO O^{-}$

The attack by $O H^{-}$ on the carbonyl group.