Question

In the given Cannizzaro reaction, the slowest step is:
$2C_{6}H_{5}CHO\overset{OH^{-}}{ \rightarrow }C_{6}H_{5}CH_{2}OH+C_{6}H_{5}COO^{-}$

• A. The attack by $OH^{-}$ on the carbonyl group.
• B. The transfer of the hydride to the carbonyl group.
• C. The exchange of protons can be slow steps.
• D. All the above.

Answer 1

Answer: (B)

The transfer of the hydride to the carbonyl group.