In the gas phase reaction, C2H5 + H2 leftharpoons C2H6, the equilibrium constant can be expressed in units of

Question

In the gas phase reaction, C2H5 + H2 leftharpoons C2H6, the equilibrium constant can be expressed in units of (A) litre-1 mole-1 (B) litre mole-1 (C) mole2 litre-2 (D) mole litre-1

Tardigrade Admin · Accepted Answer

K = ([C2H6]/[C2H4][H2]) =( text[mole/litre]/ text[mole/litre][mole/litre]) = litre/mole or litre mole-1

Q. In the gas phase reaction, $C_{2} H_{5} + H_{2} ⇌ C_{2} H_{6}$ , the equilibrium constant can be expressed in units of

litre $^{- 1}$ mole $^{- 1}$

litre mole $^{- 1}$

mole $^{2}$ litre $^{- 2}$

mole litre $^{- 1}$

$K = \frac{[ C _{2} H _{6} ]}{[ C _{2} H _{4} ] [ H _{2} ]} = \frac{[mole/litre]}{[mole/litre][mole/litre]}$
= litre/mole or litre mole $^{- 1}$

Q. In the gas phase reaction, C2​H5​+H2​⇌C2​H6​, the equilibrium constant can be expressed in units of

litre−1 mole−1

litre mole−1

mole2 litre−2

mole litre−1