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Chemistry
In the gas phase reaction, C2H5 + H2 leftharpoons C2H6, the equilibrium constant can be expressed in units of
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Q. In the gas phase reaction, $C_{2}H_{5} + H_{2} \rightleftharpoons C_{2}H_{6}$, the equilibrium constant can be expressed in units of
Equilibrium
A
litre$^{-1}$ mole$^{-1}$
0%
B
litre mole$^{-1}$
73%
C
mole$^{2}$ litre$^{-2}$
0%
D
mole litre$^{-1}$
27%
Solution:
$K =\frac {[C_{2}H_{6}]}{[C_{2}H_{4}][H_{2}]} =\frac{\text{[mole/litre]}}{\text{[mole/litre][mole/litre]}}$
= litre/mole or litre mole$^{-1}$