In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is 0.01 s. The fundamental frequency is

Question

In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is 0.01 s. The fundamental frequency is (A) 25 (B) 12.5 (C) 20 (D) 15

Tardigrade Admin · Accepted Answer

In the fundamental mode, Frequency, n = (v/λ) n = (v/4l) n = (l/t ×4l) [∵ v = (l/t)] n = (1/0.01 ×4) n = 25

Q. In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is 0.01 s. The fundamental frequency is

25

12.5

20

15

In the fundamental mode,
Frequency, $n = \frac{v}{λ}$
$n = \frac{v}{4 l}$
$n = \frac{l}{t \times 4 l} [∵ v = \frac{l}{t}]$
$n = \frac{1}{0.01 \times 4}$
$n = 25$

Q. In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is 0.01 s. The fundamental frequency is

25

12.5

20

15

In the fundamental mode, Frequency, n=λv​ n=4lv​ n=t×4ll​[∵v=tl​] n=0.01×41​ n=25

In the fundamental mode,
Frequency, $n = \frac{v}{λ}$
$n = \frac{v}{4 l}$
$n = \frac{l}{t \times 4 l} [∵ v = \frac{l}{t}]$
$n = \frac{1}{0.01 \times 4}$
$n = 25$