Question

In the formation of $N_2^{+}$from $N_2$, the electron is removed from a

• A. $\sigma$-orbital
• B. $\pi$-orbital
• C. ${\sigma }^{\ast }$-orbital
• D. ${\pi }^{\ast }$-orbital

Answer 1

Answer: (A)

$N_2$, total $e^{-}=14$
$\sigma 1s^2,\sigma \ast 1s^2,\sigma 2s^2,\sigma \ast 2s^2,\pi 2p{y}^2,\sigma 2p{x}^2,\sigma 2p{z}^2\pi \ast 2py,\sigma \ast 2px,\pi \ast 2pz$
$\Rightarrow$ since $\sigma 2pz$ is highest occupied molecular orbital $(HOMO)$ hence
$e^{-}$will be removed from $\sigma 2pz$ for the formation of $N_2^{+}$from that of $N_2$.