In the following reaction, X and Y respectively are C2H5OH xrightarrowKMnO4/H+ X xrightarrow[H2SO4/Δ]Y CH3CO2C2H5

Question

In the following reaction, X and Y respectively are C2H5OH xrightarrowKMnO4/H+ X xrightarrow[H2SO4/Δ]Y CH3CO2C2H5 (A)  CH3OH,C2H5OH  (B)  CH3CHO,CH3OH  (C)  CH3CO2H, C2H5OH  (D)  C2H4,CH3CO2H

Tardigrade Admin · Accepted Answer

underset textethanolC2H5OH + [O] xrightarrowKMnO4/H+ underset(X) textethanoic acidCH3COOH xrightarrow[H2SO4/Δ text(esterification)]C2H5OH(&gamma;) underset textethyl ethanoateCH3COOC2H5 Hence, X = CH3COOH Y = C2H5OH

Q. In the following reaction, $X$ and $Y$ respectively are
$C_{2} H_{5} O H K M n O_{4} / H^{+} X Y H_{2} S O_{4} /Δ C H_{3} C O_{2} C_{2} H_{5}$

$C H_{3} O H, C_{2} H_{5} O H$

$C H_{3} C H O, C H_{3} O H$

$C H_{3} C O_{2} H, C_{2} H_{5} O H$

$C_{2} H_{4}, C H_{3} C O_{2} H$

$ethanol C_{2} H_{5} O H + [O] K M n O_{4} / H^{+} (X) ethanoic acid C H_{3} COO H$
$C_{2} H_{5} O H (γ) H_{2} S O_{4} /Δ (esterification) ethyl ethanoate C H_{3} COO C_{2} H_{5}$
Hence, $X = C H_{3} COO H Y = C_{2} H_{5} O H$

Q. In the following reaction, X and Y respectively are C2​H5​OHKMnO4​/H+​XYH2​SO4​/Δ​CH3​CO2​C2​H5​

CH3​OH,C2​H5​OH

CH3​CHO,CH3​OH

CH3​CO2​H,C2​H5​OH

C2​H4​,CH3​CO2​H