Question

In the following reaction, $X$ and $Y$ respectively are
$C_2H_5OH \xrightarrow{KMnO_4/H^+} X \xrightarrow[H_2SO_4/\Delta]{Y} CH_3CO_2C_2H_5$

• A. $ CH_{3}OH,C_{2}H_{5}OH $
• B. $ CH_{3}CHO,CH_{3}OH $
• C. $ CH_{3}CO_{2}H,\, C_{2}H_{5}OH $
• D. $ C_{2}H_{4},CH_{3}CO_{2}H $

Answer 1

Answer: (C)

$\underset{\text{ethanol}}{C_2H_5OH} + [O] \xrightarrow{KMnO_4/H^+} \underset{(X) \text{ethanoic acid}}{CH_3COOH}$
$\xrightarrow[H_2SO_4/\Delta\text{(esterification)}]{C_2H_5OH(\gamma)} \underset{\text{ethyl ethanoate}}{CH_3COOC_2H_5}$
Hence, $X = CH_3COOH\,\, Y = C_2H_5OH$