In the following reaction (unbalanced), equivalent weight of As2S3 is related to molecular weight M by As2S3 +H+NO-3 → NO +H2O +AsO3-4 +SO2-4

Question

In the following reaction (unbalanced), equivalent weight of As2S3 is related to molecular weight M by As2S3 +H+NO-3 → NO +H2O +AsO3-4 +SO2-4 (A) (M/2) (B) (M/4) (C) (M/28) (D) (M/24)

Tardigrade Admin · Accepted Answer

As2S3 → AsO3-4 + 3SO42- O.N 2As = + 6 2×5 3×6 3s = - 6 =10 =18 Net = - Total = 28 Net change = 28 Thus, equivalent mass of As2O3 = (M/28)

Q. In the following reaction (unbalanced), equivalent weight of $A s_{2} S_{3}$ is related to molecular weight M by
$A s_{2} S_{3} + H + N O_{3}^{-} \to NO + H_{2} O + A s O_{4}^{3 -} + S O_{4}^{2 -}$

$\frac{M}{2}$

$\frac{M}{4}$

$\frac{M}{28}$

$\frac{M}{24}$

$A s_{2} S_{3} \to A s O_{4}^{3 -} + 3 S O_{4}^{2 -}$
O.N $2 A s = + 62 \times 53 \times 6$
$3 s = - 6 = 10 = 18$
Net = - Total = 28 Net change = 28
Thus, equivalent mass of $A s_{2} O_{3} = \frac{M}{28}$

Q. In the following reaction (unbalanced), equivalent weight of As2​S3​ is related to molecular weight M by As2​S3​+H+NO3−​→NO+H2​O+AsO43−​+SO42−​

2M​

4M​

28M​

24M​

As2​S3​→AsO43−​+3SO42−​ O.N 2As=+62×53×6 3s=−6=10=18 Net = - Total = 28 Net change = 28 Thus, equivalent mass of As2​O3​=28M​