In the following reaction, the final product can be prepared by two paths (.I.) and (.II.) . Which of the following statement is correct?

Question

In the following reaction, the final product can be prepared by two paths (.I.) and (.II.) . Which of the following statement is correct? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-lkjldfmev2eptvzb.jpg" /> (A) Path (I) is feasible (B) Path (II) is feasible (C) Both paths are feasible (D) Neither of the two paths is feasible

Tardigrade Admin · Accepted Answer

Since the reactant is a 3o alkyl halide, so in the presence of NaCN, it will follow E2 path rather than textS textN text2, so path (I I) is not feasible. The possible product by path (I I) is <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-lkjldfmev2epzfsc.jpg" />

Q. In the following reaction, the final product can be prepared by two paths $(I)$ and $(II)$ .
Which of the following statement is correct?

Path (I) is feasible

Path (II) is feasible

Both paths are feasible

Neither of the two paths is feasible

Since the reactant is a $3^{o}$ alkyl halide, so in the presence of $N a CN,$ it will follow E2 path rather than $S_{N} 2,$ so path $(II)$ is not feasible.
The possible product by path $(II)$ is

Q. In the following reaction, the final product can be prepared by two paths (I) and (II) . Which of the following statement is correct?