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Q. In the following reaction, the final product can be prepared by two paths $\left(\right.I\left.\right)$ and $\left(\right.II\left.\right)$ .
Which of the following statement is correct?
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Since the reactant is a $3^{o}$ alkyl halide, so in the presence of $NaCN,$ it will follow E2 path rather than $\text{S}_{\text{N}} \text{2,}$ so path $\left(I I\right)$ is not feasible.
The possible product by path $\left(I I\right)$ is
Solution