In the following reaction Fe 3 O 4+ MnO 4- longrightarrow Fe 2 O 3+ MnO 2 the number of moles of OH -liberated as per the balanced equation in the basic medium is

Question

In the following reaction Fe 3 O 4+ MnO 4- longrightarrow Fe 2 O 3+ MnO 2 the number of moles of OH -liberated as per the balanced equation in the basic medium is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/ba9c6139a91ac8467a400dff8e1074da-.png" /> ∴ Fe 3 O 4 and MnO 4-react in 6: 2 mole ratio in the balanced chemical equation 6 Fe 3 O 4+2 MnO 4-+ H 2 O longrightarrow 9 Fe 2 O 3+2 MnO 2+ OH By balancing the residual charge with OH - 6 Fe 3 O 4+2 MnO 4-+ H 2 O longrightarrow 9 Fe 2 O 3+2 MnO 2+2 OH

Q. In the following reaction Fe3​O4​+MnO4−​⟶Fe2​O3​+MnO2​ the number of moles of OH−liberated as per the balanced equation in the basic medium is

1

2

3

4

∴Fe3​O4​ and MnO4−​react in 6:2 mole ratio in the balanced chemical equation 6Fe3​O4​+2MnO4−​+H2​O⟶9Fe2​O3​+2MnO2​+OH By balancing the residual charge with OH− 6Fe3​O4​+2MnO4−​+H2​O⟶9Fe2​O3​+2MnO2​+2OH

Q. In the following reaction
$F e_{3} O_{4} + M n O_{4}^{-} ⟶ F e_{2} O_{3} + M n O_{2}$
the number of moles of $O H^{-}$ liberated as per the balanced equation in the basic medium is