In the following network, the potential at O is

Question

In the following network, the potential at O is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-mi0qsvpdvrc9wzpv.jpg" /> (A) 4 V (B) 3 V (C) 6 V (D) 4.8 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-mi0qsvpdvrc9mu0y.jpg" /> Let the potential at O is V0. Application of Kirchhoff's first law at junction O gives (8 - V0/2)=(V0 - 4/4)+(V0 - 2/2) =(V0 - 4 + 2 V0 - 4/4) (4 (8 - V0)/2)=V0-4+2V0-4 16-2V0=3V0-8 16+8=5V0 V0=(24/5)=4.8 V

Q. In the following network, the potential at $O$ is

$4 V$

$3 V$

$6 V$

$4.8 V$

Q. In the following network, the potential at O is

4V

3V

6V

4.8V

Let the potential at O is V0​. Application of Kirchhoff's first law at junction O gives 28−V0​​=4V0​−4​+2V0​−2​ =4V0​−4+2V0​−4​ 24(8−V0​)​=V0​−4+2V0​−4 16−2V0​=3V0​−8 16+8=5V0​ V0​=524​=4.8V

Q. In the following network, the potential at $O$ is

$4 V$

$3 V$

$6 V$

$4.8 V$