In the following monobromination reaction, the number of possible chiral products are

Question

In the following monobromination reaction, the number of possible chiral products are <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-umdipcczyewzl6uz.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

It is a free radical reaction in which different type of hydrogen is substituted by bromine free radical So by doing this we get chiral carbons those are optically active and each chiral carbon gives two mirror images product. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-umdipcczyewz0od1.jpg" />

Q. In the following monobromination reaction, the number of possible chiral products are

It is a free radical reaction in which different type of hydrogen is substituted by bromine free radical So by doing this we get chiral carbons those are optically active and each chiral carbon gives two mirror images product.

It is a free radical reaction in which different type of hydrogen is substituted by bromine free radical
So by doing this we get chiral carbons those are optically active and each chiral carbon gives two mirror images product.