In the following disproportionation of Cl2 in basic medium Cl2 +2KOH → KCl +KClO +H2O Equivalent mass of Cl2 is

Question

In the following disproportionation of Cl2 in basic medium Cl2 +2KOH → KCl +KClO +H2O Equivalent mass of Cl2 is (A) 35.50 (B) 71.00 (C) 47.33 (D) 11.83

Tardigrade Admin · Accepted Answer

In a disproportionation reaction
net equivalent mass= E (oxidation part) + E (reduction part)

	Change in O.N	Equivalent weight
$\frac{1}{2 _{o}} C l_{2} \to C l_{- 1}^{-}$	1	$= \frac{M}{2}$
$\frac{1}{2 _{o}} C l_{2} \to Cl O_{+ 1}^{-}$	1	$= \frac{M}{2}$

Net

= \frac{M}{2} + \frac{M}{2} = M = 71.0

Q. In the following disproportionation of $C l_{2}$ in basic medium
$C l_{2} + 2 K O H \to K Cl + K ClO + H_{2} O$
Equivalent mass of $C l_{2}$ is

$35.50$

$71.00$

$47.33$

$11.83$

Q. In the following disproportionation of Cl2​ in basic medium Cl2​+2KOH→KCl+KClO+H2​O Equivalent mass of Cl2​ is

35.50

71.00

47.33

11.83

In a disproportionation reaction net equivalent mass= E (oxidation part) + E (reduction part) Change in O.N Equivalent weight 2o​1​Cl2​→Cl−1−​ 1 =2M​ 2o​1​Cl2​→ClO+1−​ 1 =2M​ Net =2M​+2M​=M=71.0

Q. In the following disproportionation of $C l_{2}$ in basic medium
$C l_{2} + 2 K O H \to K Cl + K ClO + H_{2} O$
Equivalent mass of $C l_{2}$ is

$35.50$

$71.00$

$47.33$

$11.83$