Q.
In the following disproportionation of $Cl_{2}$ in basic medium
$Cl_{2} +2KOH \to KCl +KClO +H_{2}O$
Equivalent mass of $Cl_{2}$ is
Redox Reactions
Solution:
In a disproportionation reaction
net equivalent mass= E (oxidation part) + E (reduction part)
Change in O.N
Equivalent weight
$\frac{1}{2_{o}}Cl_{2}\to Cl_{-1}^{-}$
1
$=\frac{M}{2}$
$\frac{1}{2_{o}}Cl_{2}\to ClO_{+1}^{-}$
1
$=\frac{M}{2}$
Net $=\frac{M}{2}+\frac{M}{2}=M=71.0$
| Change in O.N | Equivalent weight | |
|---|---|---|
| $\frac{1}{2_{o}}Cl_{2}\to Cl_{-1}^{-}$ | 1 | $=\frac{M}{2}$ |
| $\frac{1}{2_{o}}Cl_{2}\to ClO_{+1}^{-}$ | 1 | $=\frac{M}{2}$ |