In the following change, 3Fe+4H2O arrow Fe3O4+4H2 If the atomic weight of iron is 56, then its equivalent weight will be

Question

In the following change, 3Fe+4H2O arrow Fe3O4+4H2 If the atomic weight of iron is 56, then its equivalent weight will be (A) 42 (B) 21 (C) 63 (D) 84

Tardigrade Admin · Accepted Answer

In the given reaction iron is undergoing oxidation. 3Fe0 arrow 3Fe+ (. 8 / 3 .)+8e- So Equivalentweight=(Atomic weight/n - factor)=(M/8 / 3)=(56 × 3/8)=21 .

Q. In the following change,
$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$
If the atomic weight of iron is 56, then its equivalent weight will be

42

21

63

84

In the given reaction iron is undergoing oxidation.
$3 F e^{0} \to 3 F e_{+ (8/3)} + 8 e^{-}$
So $Eq u i v a l e n tw e i g h t = \frac{A t o mi c w e i g h t}{n - f a c t or} = \frac{M}{8/3} = \frac{56 \times 3}{8} = 21$ .

Q. In the following change, 3Fe+4H2​O→Fe3​O4​+4H2​ If the atomic weight of iron is 56, then its equivalent weight will be

42

21

63

84

In the given reaction iron is undergoing oxidation. 3Fe0→3Fe+(8/3)​+8e− So Equivalentweight=n−factorAtomicweight​=8/3M​=856×3​=21 .

Q. In the following change,
$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$
If the atomic weight of iron is 56, then its equivalent weight will be

In the given reaction iron is undergoing oxidation.
$3 F e^{0} \to 3 F e_{+ (8/3)} + 8 e^{-}$
So $Eq u i v a l e n tw e i g h t = \frac{A t o mi c w e i g h t}{n - f a c t or} = \frac{M}{8/3} = \frac{56 \times 3}{8} = 21$ .