Q.
In the following change,
$3Fe+4H_{2}O \rightarrow Fe_{3}O_{4}+4H_{2}$
If the atomic weight of iron is 56, then its equivalent weight will be
NTA AbhyasNTA Abhyas 2022
Solution:
In the given reaction iron is undergoing oxidation.
$3Fe^{0} \rightarrow 3Fe_{}^{+ \left(\right. 8 / 3 \left.\right)}+8e^{-}$
So $Equivalentweight=\frac{Atomic weight}{n - factor}=\frac{M}{8 / 3}=\frac{56 \times 3}{8}=21$ .
$3Fe^{0} \rightarrow 3Fe_{}^{+ \left(\right. 8 / 3 \left.\right)}+8e^{-}$
So $Equivalentweight=\frac{Atomic weight}{n - factor}=\frac{M}{8 / 3}=\frac{56 \times 3}{8}=21$ .