In the following cases, equivalent weight of the underlined may be equal to molecular weight

Question

In the following cases, equivalent weight of the underlined may be equal to molecular weight (A)  underline2 CuSO 4+4 KI arrow Cu 2 I 2+2 K 2 SO 4+ I 2 (B)  underline2 Na 2 S 2 O 3+ I 2 arrow 2 NaI + Na 2 S 4 O 6 (C)  underline P 4+3 NaOH +3 H 2 O arrow 3 NaH 2 PO 2+ PH 3 (D)  underline H 2 SO 4+ NaOH arrow NaHSO 4+ H 2 O

Tardigrade Admin · Accepted Answer

Correct answer is (a) underline2 CuSO 4+4 KI arrow Cu 2 I 2+2 K 2 SO 4+ I 2Correct answer is (b) underline2 Na 2 S 2 O 3+ I 2 arrow 2 NaI + Na 2 S 4 O 6Correct answer is (d) underline H 2 SO 4+ NaOH arrow NaHSO 4+ H 2 O

Q. In the following cases, equivalent weight of the underlined may be equal to molecular weight

$\underline{2 C u S O_{4}} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}$

$\underline{2 N a_{2} S_{2} O_{3}} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}$

$\underline{P_{4}} + 3 N a O H + 3 H_{2} O \to 3 N a H_{2} P O_{2} + P H_{3}$

$\underline{H_{2} S O_{4}} + N a O H \to N a H S O_{4} + H_{2} O$

Correct answer is (a) $\underline{2 C u S O_{4}} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}$ Correct answer is (b) $\underline{2 N a_{2} S_{2} O_{3}} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}$ Correct answer is (d) $\underline{H_{2} S O_{4}} + N a O H \to N a H S O_{4} + H_{2} O$

Q. In the following cases, equivalent weight of the underlined may be equal to molecular weight

2CuSO4​​+4KI→Cu2​I2​+2K2​SO4​+I2​

2Na2​S2​O3​​+I2​→2NaI+Na2​S4​O6​

P4​​+3NaOH+3H2​O→3NaH2​PO2​+PH3​

H2​SO4​​+NaOH→NaHSO4​+H2​O

Correct answer is (a) 2CuSO4​​+4KI→Cu2​I2​+2K2​SO4​+I2​ Correct answer is (b) 2Na2​S2​O3​​+I2​→2NaI+Na2​S4​O6​ Correct answer is (d) H2​SO4​​+NaOH→NaHSO4​+H2​O

$\underline{2 C u S O_{4}} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}$

$\underline{2 N a_{2} S_{2} O_{3}} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}$

$\underline{P_{4}} + 3 N a O H + 3 H_{2} O \to 3 N a H_{2} P O_{2} + P H_{3}$

$\underline{H_{2} S O_{4}} + N a O H \to N a H S O_{4} + H_{2} O$

Correct answer is (a) $\underline{2 C u S O_{4}} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}$ Correct answer is (b) $\underline{2 N a_{2} S_{2} O_{3}} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}$ Correct answer is (d) $\underline{H_{2} S O_{4}} + N a O H \to N a H S O_{4} + H_{2} O$