In the figure shown, the potential difference across the diodes D1, D2 and the resistor of resistance 0.4 Ω are P, Q and R volts, respectively. Find P+Q+R. (Assume all diodes are ideal)

Question

In the figure shown, the potential difference across the diodes D1, D2 and the resistor of resistance 0.4 Ω are P, Q and R volts, respectively. Find P+Q+R. (Assume all diodes are ideal) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Electrical equivalent: D1 and D4 are reverse biased and D2 and D3 are forward biased. i=(1.5/0.2+0.4)=2.5 A <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/52f7d2523e73cb5453934fe2914599d6-.png" />

Q. In the figure shown, the potential difference across the diodes $D_{1}, D_{2}$ and the resistor of resistance $0.4 Ω$ are $P$ , $Q$ and $R$ volts, respectively. Find $P + Q + R$ . (Assume all diodes are ideal)

Electrical equivalent:
$D_{1}$ and $D_{4}$ are reverse biased and $D_{2}$ and $D_{3}$ are forward biased.
$i = \frac{1.5}{0.2 + 0.4} = 2.5 A$

Q. In the figure shown, the potential difference across the diodes D1​,D2​ and the resistor of resistance 0.4Ω are P, Q and R volts, respectively. Find P+Q+R. (Assume all diodes are ideal)

Electrical equivalent: D1​ and D4​ are reverse biased and D2​ and D3​ are forward biased. i=0.2+0.41.5​=2.5A

Q. In the figure shown, the potential difference across the diodes $D_{1}, D_{2}$ and the resistor of resistance $0.4 Ω$ are $P$ , $Q$ and $R$ volts, respectively. Find $P + Q + R$ . (Assume all diodes are ideal)

Electrical equivalent:
$D_{1}$ and $D_{4}$ are reverse biased and $D_{2}$ and $D_{3}$ are forward biased.
$i = \frac{1.5}{0.2 + 0.4} = 2.5 A$