Question

In the figure shown, the capacity of the condenser $C$ is $2\mu F$ . The current in $2\Omega$ resistor is

• A. $9A$
• B. $0.9A$
• C. $\frac{1}{9}A$
• D. $\frac{1}{0.9}A$

Answer 1

Answer: (B)

Resistance in uppermost branch $R\text{ = }\frac{2\times 3}{2+3}=\frac{6}{5}=1.2\Omega$
After a long time, branch with the capacitor can be considered open circuited
Hence,
$R_{eq}=2.8+1.2=4\Omega$
$I\text{= }\frac{V}{R}=\frac{6}{4}=\frac{3}{2}A$
$I_{2\Omega }\text{= }\frac{I{R}_2}{R_1+R_2}=\frac{\frac{3}{2}\times 3}{5}A$
$I_{2\Omega }\text{ = }\frac{9}{10}=0.9\text{ A}$