In the figure shown, the block of mass m is at rest relative to the wedge of mass M and the wedge is at rest with respect to ground. This implies that

Question

In the figure shown, the block of mass m is at rest relative to the wedge of mass M and the wedge is at rest with respect to ground. This implies that (A) Net force applied by m on M is m g. (B) Normal force applied by m on M is m g. (C) Force of friction applied by m on M is m g. (D) None of the above.

Tardigrade Admin · Accepted Answer

N=m g cos θ, f=m g sin θ Net force applied by M on m (or m on M ): F =√N2+f2 =√(m g cos θ)2+(m g sin θ)2 =m g

Q. In the figure shown, the block of mass $m$ is at rest relative to the wedge of mass $M$ and the wedge is at rest with respect to ground. This implies that

Net force applied by m on M is m g.

Normal force applied by m on M is m g.

Force of friction applied by m on M is m g.

None of the above.

$N = m g cos θ, f = m g sin θ$
Net force applied by $M$ on $m$ (or $m$ on $M$ ):
$F = N^{2} + f^{2}$
$= (m g cos θ)^{2} + (m g sin θ)^{2}$
$= m g$

Q. In the figure shown, the block of mass m is at rest relative to the wedge of mass M and the wedge is at rest with respect to ground. This implies that