In the figure acceleration of A is 1 m/s2 upwards, acceleration of B is 7 m/s2 upwards and acceleration of C is 2 m/s2 upwards. The acceleration of D will be

Question

In the figure acceleration of A is 1 m/s2 upwards, acceleration of B is 7 m/s2 upwards and acceleration of C is 2 m/s2 upwards. The acceleration of D will be <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/3bb5e028b7f26a0f0595c33858962aef-.png" /> (A) 7 m/s2 downwards (B) 2 m/s2 downwards (C) 10 m/s2 downwards (D) 8 m/s2 downwards

Tardigrade Admin · Accepted Answer

Acceleration of pulley P ap=(aA+aB/2) =(1+7/2) =4 m/s2 (upward) Acceleration pulley Q will be 4 m/s2 downwards <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2321303390d593c5aa8f2f8663820245-.png" /> aQ=(aD - ac/2) 4=(aD-2/2) ⇒ aD=10 m/s2 (â)

Q. In the figure acceleration of $A$ is $1 m / s^{2}$ upwards, acceleration of $B$ is $7 m / s^{2}$ upwards and acceleration of $C$ is $2 m / s^{2}$ upwards. The acceleration of D will be

$7 m / s^{2}$ downwards

$2 m / s^{2}$ downwards

$10 m / s^{2}$ downwards

$8 m / s^{2}$ downwards

Acceleration of pulley $P$

$a_{p} = \frac{a _{A} + a _{B}}{2}$

$= \frac{1 + 7}{2}$

$= 4 m / s^{2}$ (upward)

Acceleration pulley Q will be $4 m / s^{2}$ downwards

$a_{Q} = \frac{a _{D} - a _{c}}{2}$

$4 = \frac{a _{D} - 2}{2}$

$\Rightarrow a_{D} = 10 m / s^{2} (↓)$

Q. In the figure acceleration of A is 1m/s2 upwards, acceleration of B is 7m/s2 upwards and acceleration of C is 2m/s2 upwards. The acceleration of D will be

7m/s2 downwards

2m/s2 downwards

10m/s2 downwards

8m/s2 downwards