In the figure, a block of weight 60 N is placed on a rough surface. The coefficient of friction between the block and the surfaces is 0.5. What should be the weight W such that the block does not slip on the surface?

Question

In the figure, a block of weight 60 N is placed on a rough surface. The coefficient of friction between the block and the surfaces is 0.5. What should be the weight W such that the block does not slip on the surface? <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d83b87a12c2db9d69f83053c22573ff4-.png" /> (A) 60 N (B) (60/√2)N (C) 30 N (D) (30/√2)N

Tardigrade Admin · Accepted Answer

Frictional force: F=μ R = 0.5 × mg = 0.5× 60=30 N Now F=T1=T2 cos 45° or 30=T2 cos 45° and W=T2 sin 45° Solving them we get W=30 N

Q. In the figure, a block of weight $60 N$ is placed on a rough surface. The coefficient of friction between the block and the surfaces is $0.5$ . What should be the weight $W$ such that the block does not slip on the surface?

$60 N$

$\frac{60}{2} N$

$30 N$

$\frac{30}{2} N$

Frictional force:

$F = μ R = 0.5 \times m g$
$= 0.5 \times 60 = 30 N$

Now $F = T_{1} = T_{2} cos 4 5^{\circ}$

or $30 = T_{2} cos 4 5^{\circ}$

and $W = T_{2}$ $s in 4 5^{\circ}$

Solving them we get $W = 30 N$

Q. In the figure, a block of weight 60N is placed on a rough surface. The coefficient of friction between the block and the surfaces is 0.5. What should be the weight W such that the block does not slip on the surface?

60N

2​60​N

30N

2​30​N