In the experiment on photoelectric effect, the graph between EK( max ) and v is found to be a straight line as shown in figure. The threshold frequency and Planck's constant according to this graph are

Question

In the experiment on photoelectric effect, the graph between EK( max ) and v is found to be a straight line as shown in figure. The threshold frequency and Planck's constant according to this graph are (A) 3.33 × 1018 s -1, 6 × 10-34 J - s (B) 6 × 1018 s -1, 6 × 10-34 J - s (C) 2.66 × 1018 s -1, 4 × 10-34 J - s (D) 4 × 1018 s -1, 3 × 10-34 J - s

Tardigrade Admin · Accepted Answer

K max =h v-W ω is the intercept on y-axis and h is the slope. ∴ h=(2.4 × 10-15/4 × 1018)=6 × 10-34 Js W=2 × 10-15 J ⇒ h v 0=2 × 10-15 or v 0=3.33 × 1018 s

Q. In the experiment on photoelectric effect, the graph between $E_{K (m a x)}$ and $v$ is found to be a straight line as shown in figure. The threshold frequency and Planck's constant according to this graph are

$3.33 \times 1 0^{18} s^{- 1}, 6 \times 1 0^{- 34} J - s$

$6 \times 1 0^{18} s^{- 1}, 6 \times 1 0^{- 34} J - s$

$2.66 \times 1 0^{18} s^{- 1}, 4 \times 1 0^{- 34} J - s$

$4 \times 1 0^{18} s^{- 1}, 3 \times 1 0^{- 34} J - s$

$K_{m a x} = h v - W$
$ω$ is the intercept on $y$ -axis and $h$ is the slope.
$∴ h = \frac{2.4 \times 1 0 ^{- 15}}{4 \times 1 0 ^{18}} = 6 \times 1 0^{- 34} J s$
$W = 2 \times 1 0^{- 15} J$
$\Rightarrow h v_{0} = 2 \times 1 0^{- 15}$
or $v_{0} = 3.33 \times 1 0^{18} s$

Q. In the experiment on photoelectric effect, the graph between EK(max)​ and v is found to be a straight line as shown in figure. The threshold frequency and Planck's constant according to this graph are

3.33×1018s−1,6×10−34J−s

6×1018s−1,6×10−34J−s

2.66×1018s−1,4×10−34J−s

4×1018s−1,3×10−34J−s