In the expansion of (a+b)n, if n is odd, then middle term(s) is/are

Question

In the expansion of (a+b)n, if n is odd, then middle term(s) is/are (A) ((n+1/2)) text th term (B) ((n+1/2)+1) text th term (C) Both (a) and (b) (D) Neither (a) nor (b)

Tardigrade Admin · Accepted Answer

Regarding the middle term in the expansion (a+b)n, we have if n is odd, then (n+1) is even, so there will be two middle terms in the expansion, namely ((n+1/2)) text th term and ((n+1/2)+1) text th term

Q. In the expansion of $(a + b)^{n}$ , if $n$ is odd, then middle term(s) is/are

$(\frac{n + 1}{2})^{th}$ term

$(\frac{n + 1}{2} + 1)^{th}$ term

Both (a) and (b)

Neither (a) nor (b)

Regarding the middle term in the expansion $(a + b)^{n}$ , we have if $n$ is odd, then $(n + 1)$ is even, so there will be two middle terms in the expansion, namely $(\frac{n + 1}{2})^{th}$ term and $(\frac{n + 1}{2} + 1)^{th}$ term

Q. In the expansion of (a+b)n, if n is odd, then middle term(s) is/are

(2n+1​)th term

(2n+1​+1)th term