In the electrolysis of water, one faraday of electrical energy would evolve :

Question

In the electrolysis of water, one faraday of electrical energy would evolve : (A) one mole of oxygen (B) one gram atom of oxygen (C) 8 g of oxygen (D) 22.4 Lot oxygen

Tardigrade Admin · Accepted Answer

Hydrolysis of water can be represented by the following equations? 2H2Oleftharpoons O2+4H++4e- ∵ 4 faraday of charge liberate O2=32 g ∴ 1 faraday of charge liberate O2=(32/4)=8g

Q. In the electrolysis of water, one faraday of electrical energy would evolve :

one mole of oxygen

one gram atom of oxygen

8 g of oxygen

22.4 Lot oxygen

Hydrolysis of water can be represented by the following equations? $2 H_{2} O ⇌ O_{2} + 4 H^{+} + 4 e^{-}$ $∵$ 4 faraday of charge liberate $O_{2} = 32 g$ $∴$ 1 faraday of charge liberate $O_{2} = \frac{32}{4} = 8 g$

Q. In the electrolysis of water, one faraday of electrical energy would evolve :

one mole of oxygen

one gram atom of oxygen

8 g of oxygen

22.4 Lot oxygen

Hydrolysis of water can be represented by the following equations? 2H2​O⇌O2​+4H++4e− ∵ 4 faraday of charge liberate O2​=32g ∴ 1 faraday of charge liberate O2​=432​=8g

Hydrolysis of water can be represented by the following equations? $2 H_{2} O ⇌ O_{2} + 4 H^{+} + 4 e^{-}$ $∵$ 4 faraday of charge liberate $O_{2} = 32 g$ $∴$ 1 faraday of charge liberate $O_{2} = \frac{32}{4} = 8 g$