In the electrolysis of aqueous solution of CuSO4 using copper electrodes, the process taking place at the anode is

Question

In the electrolysis of aqueous solution of CuSO4 using copper electrodes, the process taking place at the anode is (A)  SO42-arrow SO4+2e-  (B)  Cuarrow Cu++e-  (C)  2OH-arrow H2O+(1/2)O2+2e-  (D)  Cuarrow Cu2++2e-

Tardigrade Admin · Accepted Answer

When aqueous solution of CuSO 4 is subjected to electrolysis, the following reactions take place at cathode and anode. CuSO 4 arrow Cu 2++ SO 42- At cathode: C u2++2 e- arrow C u At anode: 2 OH - arrow H 2 O +(1/2) O 2+2 e-

Q. In the electrolysis of aqueous solution of $C u S O_{4}$ using copper electrodes, the process taking place at the anode is

$S O_{4}^{2 -} \to S O_{4} + 2 e^{-}$

$C u \to C u^{+} + e^{-}$

$2 O H^{-} \to H_{2} O + \frac{1}{2} O_{2} + 2 e^{-}$

$C u \to C u^{2 +} + 2 e^{-}$

When aqueous solution of $C u S O_{4}$ is subjected to electrolysis, the following reactions take place at cathode and anode.
$C u S O_{4} \to C u^{2 +} + S O_{4}^{2 -}$
At cathode: $C u^{2 +} + 2 e^{-} \to C u$
At anode: $2 O H^{-} \to H_{2} O + \frac{1}{2} O_{2} + 2 e^{-}$

Q. In the electrolysis of aqueous solution of CuSO4​ using copper electrodes, the process taking place at the anode is

SO42−​→SO4​+2e−

Cu→Cu++e−

2OH−→H2​O+21​O2​+2e−

Cu→Cu2++2e−